3x^2+26x+120=12

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Solution for 3x^2+26x+120=12 equation:



3x^2+26x+120=12
We move all terms to the left:
3x^2+26x+120-(12)=0
We add all the numbers together, and all the variables
3x^2+26x+108=0
a = 3; b = 26; c = +108;
Δ = b2-4ac
Δ = 262-4·3·108
Δ = -620
Delta is less than zero, so there is no solution for the equation

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